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| // Ladders and Snakes | |
| // Solution by Jacob Plachta | |
| using namespace std; | |
| template<typename T> T Abs(T x) { return(x<0 ? -x : x); } | |
| template<typename T> T Sqr(T x) { return(x*x); } | |
| string plural(string s) { return(Sz(s) && s[Sz(s)-1]=='x' ? s+"en" : s+"s"); } | |
| const int INF = (int)1e9; | |
| const LD EPS = 1e-12; | |
| const LD PI = acos(-1.0); | |
| bool Read(int &x) | |
| { | |
| char c,r=0,n=0; | |
| x=0; | |
| for(;;) | |
| { | |
| c=GETCHAR(); | |
| if ((c<0) && (!r)) | |
| return(0); | |
| if ((c=='-') && (!r)) | |
| n=1; | |
| else | |
| if ((c>='0') && (c<='9')) | |
| x=x*10+c-'0',r=1; | |
| else | |
| if (r) | |
| break; | |
| } | |
| if (n) | |
| x=-x; | |
| return(1); | |
| } | |
| struct Dinic { | |
| struct Edge { | |
| int to, rev, c, f; | |
| Edge(int to, int rev, int c, int f) : to(to), rev(rev), c(c), f(f) {} | |
| }; | |
| vector<int> lvl, ptr, q; | |
| vector< vector<Edge> > adj; | |
| Dinic(int n) : lvl(n), ptr(n), q(n), adj(n) {} | |
| void addEdge(int a, int b, int c) { | |
| adj[a].pb(Edge(b, Sz(adj[b]), c, 0)); | |
| adj[b].pb(Edge(a, Sz(adj[a]) - 1, 0, 0)); | |
| } | |
| int dfs(int v, int t, int f) { | |
| if (v == t || !f) return f; | |
| for (int& i = ptr[v]; i < Sz(adj[v]); i++) { | |
| Edge& e = adj[v][i]; | |
| if (lvl[e.to] == lvl[v] + 1) { | |
| if (int p = dfs(e.to, t, min(f, e.c - e.f))) { | |
| e.f += p, adj[e.to][e.rev].f -= p; | |
| return p; | |
| } | |
| } | |
| } | |
| return 0; | |
| } | |
| int calc(int s, int t) { | |
| int L, flow = 0; q[0] = s; | |
| Fox(L,31) { | |
| do { | |
| lvl = ptr = vector<int>(Sz(q)); | |
| int qi = 0, qe = lvl[s] = 1; | |
| while (qi < qe && !lvl[t]) { | |
| int i, v = q[qi++]; | |
| Fox(i,Sz(adj[v])) { | |
| Edge e=adj[v][i]; | |
| if (!lvl[e.to] && (e.c - e.f) >> (30 - L)) { | |
| q[qe++] = e.to, lvl[e.to] = lvl[v] + 1; | |
| } | |
| } | |
| } | |
| while (int p = dfs(s, t, INF)) flow += p; | |
| } while (lvl[t]); | |
| } | |
| return flow; | |
| } | |
| }; | |
| int main() | |
| { | |
| if (DEBUG) | |
| freopen("in.txt","r",stdin); | |
| // vars | |
| int T,t; | |
| int N,H; | |
| int i,j,k; | |
| int X[LIM],A[LIM],B[LIM]; | |
| // testcase loop | |
| Read(T); | |
| Fox1(t,T) | |
| { | |
| // input | |
| Read(N),Read(H); | |
| Fox(i,N) | |
| Read(X[i]),Read(A[i]),Read(B[i]); | |
| // construct flow graph | |
| Dinic D(N+2); | |
| Fox(i,N) | |
| { | |
| // connected to bottom? | |
| if (A[i]==0) | |
| D.addEdge(N,i,1e7); | |
| // connected to top? | |
| if (B[i]==H) | |
| D.addEdge(i,N+1,1e7); | |
| // consider connections to other ladders | |
| Fox(j,N) | |
| if (X[i]<X[j]) | |
| { | |
| // compute combined length of connecting, unobstructed y-coordinate intervals | |
| vector<pair<int,PR> > E; | |
| Fox(k,N) | |
| if ((X[i]<=X[k]) && (X[k]<=X[j])) | |
| { | |
| E.pb(mp(A[k],mp(1,k))); | |
| E.pb(mp(B[k],mp(0,k))); | |
| } | |
| int s=0; | |
| set<int> S; | |
| sort(All(E)); | |
| Fox(k,Sz(E)) | |
| { | |
| if (E[k].y.x) | |
| S.insert(E[k].y.y); | |
| else | |
| S.erase(E[k].y.y); | |
| if ((Sz(S)==2) && (S.count(i)) && (S.count(j))) | |
| s+=E[k+1].x-E[k].x; | |
| } | |
| if (s) | |
| { | |
| D.addEdge(i,j,s); | |
| D.addEdge(j,i,s); | |
| } | |
| } | |
| } | |
| // compute min cut | |
| int ans=D.calc(N,N+1); | |
| if (ans>=1e7) | |
| ans=-1; | |
| // output | |
| printf("Case #%d: %d\n",t,ans); | |
| } | |
| return(0); | |
| } |